This code isn't working. Anyone have any ideas

[chersey]

PHP Version 5

Here’s the error I get
Parse error: syntax error, unexpected ‘=’

<?php $username="xxxxxxxxxx"; $password="xxxxxxxx"; $database="xxxxxxxxxxx"; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM tablename"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); echo "Database Output

"; $i=0; while ($i < $num) { $field1-name=mysql_result($result,$i,"field1-name"); <=========Error points to this line $field2-name=mysql_result($result,$i,"field2-name"); $field3-name=mysql_result($result,$i,"field3-name"); $field4-name=mysql_result($result,$i,"field4-name"); $field5-name=mysql_result($result,$i,"field5-name"); echo "$field1-name $field2-name2
$field3-name
$field4-name
$field5-name

---

"; $i++; } ?>

[sergo_bero]

$field1-name

if it is a variable this is an error , - is not allowed in variable names , replace it by _