im trying to display the sql table but i get these warnings please help im sorta on a deadline :o :o :o
and how do you tell it to pull from table
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/u160665993/public_html/argylewallet/testpanel.php on line 485
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/u160665993/public_html/argylewallet/testpanel.php on line 486
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/u160665993/public_html/argylewallet/testpanel.php on line 487
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/u160665993/public_html/argylewallet/testpanel.php on line 488
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/u160665993/public_html/argylewallet/testpanel.php on line 489
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/u160665993/public_html/argylewallet/testpanel.php on line 490
Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/u160665993/public_html/argylewallet/testpanel.php on line 491
[php]<?php
mysql_connect(“sql server”,“u160665993_adds”,“addsadds”) or die(mysql_error());
mysql_select_db(“u160665993_adds”);
$query=“SELECT * FROM data”;
$result=mysql_query($query);
[/php]
Of course, I am assuming that you want all of the data returned to be displayed…
Also, there was no variable showing for “Service Rating”, so you have to fix that…
Good luck…
with your code i recieve back Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in /home/u160665993/public_html/argylewallet/testpanel.php on line 480
here its the code 475.[php]<?php476.mysql_connect("mysql.hostchick.co.uk","u160665993_adds","addsadds") or die(mysql_error());477.mysql_select_db("u160665993_adds");478.$query="argylebia";479.$result=mysql_query($query);480.echo "Categorie is $classified";echo "