I have a standard search form that goes to a results page with pagination, but when the first results show up it produces Undefined index: pagenum for the second line of the results code. When I click on a link to view more of the results the code runs correctly and doesn’t show the error message.
Here is the search function.
[php]
Search
Seach for: in Need Give [/php]Here is the results code. Note that it isn’t connected to the search code like the search code should. I left the search code to not send over any result limiting variables. This makes the search function into a fancy link so only the results code will run and echo all results. That will allow me to solve other errors before I try to narrow the search function.
[php] <?php
$pagenum = $_GET[‘pagenum’];
// Connects to your Database
mysql_connect(“localhost”, “”, “”) or die(mysql_error());
mysql_select_db(“test”) or die(mysql_error());
//This checks to see if there is a page number. If not, it will set it to page 1
if (!(isset($pagenum)))
{
$pagenum = 1;
}
//Here we count the number of results
//Edit $data to be your query
$data = mysql_query(“SELECT * FROM need”) or die(mysql_error());
$rows = mysql_num_rows($data);
//This is the number of results displayed per page
$page_rows = 4;
//This tells us the page number of our last page
$last = ceil($rows/$page_rows);
//this makes sure the page number isn’t below one, or more than our maximum pages
if ($pagenum < 1)
{
$pagenum = 1;
}
elseif ($pagenum > $last)
{
$pagenum = $last;
}
//This sets the range to display in our query
$max = ‘limit ’ .($pagenum - 1) * $page_rows .’,’ .$page_rows;
//This is your query again, the same one… the only difference is we add $max into it
$data_p = mysql_query(“SELECT * FROM need $max”) or die(mysql_error());
//This is where you display your query results
while($info = mysql_fetch_array( $data_p ))
{
Print $info[‘needname’];
echo “
”;
}
echo “
”;
// This shows the user what page they are on, and the total number of pages
echo " --Page $pagenum of $last--
";
// First we check if we are on page one. If we are then we don’t need a link to the previous page or the first page so we do nothing. If we aren’t then we generate links to the first page, and to the previous page.
if ($pagenum == 1)
{
}
else
{
echo " <a href=’{$_SERVER[‘PHP_SELF’]}?pagenum=1’> <<-First ";
echo " ";
$previous = $pagenum-1;
echo " <a href=’{$_SERVER[‘PHP_SELF’]}?pagenum=$previous’> <-Previous ";
}
//just a spacer
echo " ---- ";
//This does the same as above, only checking if we are on the last page, and then generating the Next and Last links
if ($pagenum == $last)
{
}
else {
$next = $pagenum+1;
echo " <a href=’{$_SERVER[‘PHP_SELF’]}?pagenum=$next’>Next -> ";
echo " ";
echo " <a href=’{$_SERVER[‘PHP_SELF’]}?pagenum=$last’>Last ->> ";
}
?> [/php]
I also want to stack the search function on top of the results function in the same file to make it easier for the user. I have to use an action that will let the search for go back to the same file to run the other code, but when I use test it the server shows a page with object not found. Can anyone help me solve these two problems.
Thanks.
