Okay so here is where my problem is occurring. I have a set of code right here:
[php]$gSelect = $_POST[‘location’];
echo"
";
echo “
| Year |
Time |
$gSelect |
”;[/php]
This sets up a columned table that allows data to be displayed in a neat fashion once the users select their data restrictions. All of these restrictions are within drop down menus. $gSelect represents the drop down menu where users can select a location (Local Oh Counties, Ohio, US). Here is the drop down menu I am talking about:
[php]
Please specify a location
Fayette County (IN)
Randolph County (IN)
Rush County (IN)
Union County (IN)
Wayne County (IN)
Local Indiana Counties
Indiana
Butler County (OH)
Darke County (OH)
Mercer County (OH)
Preble County (OH)
Local Ohio Counties
Ohio
United States
[/php]
As you can see, the option value names (which are equal to some of my columns in my database) are different from the actual names that show up in my drop down menu (‘Rush’ versus "Rush County (IN) for instance). Echo “$gSelect”; prints the option value name for the selection. Instead, I want it to print the name that shows up in my drop down menu. Is there anyway I can fix this? Any help would be greatly appreciated. Also, I use $gSelect to set up a query to select the column for my database as well (SELECT $gSelect from table; for example), so I would like to leave $gSelect alone if possible.
Would anything like this work?
[php]echo"
";
echo “
| Year |
Time |
$_POST[‘Location[name]’] |
”;[/php]
I am just trying to figure out how to display the drop down menu name instead of the value name without changing $gSelect since I use it in queries.
