PHP Functional programming

[keenlearner]

I need to to a little functional programming, my question is in the code. Thanks.

[code]<?php
function print1($arg1, $arg2)
{
echo 'Print 1 function : ';
var_dump($arg1);
var_dump($arg2);
}

function print2($arg1,$arg2)
{
echo 'Print 2 function : ';
var_dump($arg1);
var_dump($arg2);
}

function applyOne($arg1,$funcName)
{
if(is_array($arg1)) $code = “return $funcName(/How should I write here for array ? Thanks/ ,$arg2)”;
else $code = “return $funcName(”$arg1", $arg2);";

return create_function(’$arg2’, $code);
}

//this is working
$printFunction = applyOne(‘string 1’, ‘print1’);
$printFunction(‘arg2 string’);

//'This is not working, how to make it work for array ? But note that the array may contain other type of objects, not just string. Thanks.
class obj {
function __construct(){}
}
$obj = new obj();
$printFunction = applyOne(array($obj), ‘print2’);
$printFunction(‘arg2 string’);

?>[/code]

Can I have the array that has been passed to stay alive until passed to the print function ?

[keenlearner]

Thanks I got the solution, pretty cool.

[PHP]function print1($arg1, $arg2)
{
echo 'Print 1 function : ';
var_dump($arg1);
var_dump($arg2);
echo ‘
’;
}

function print2($arg1,$arg2)
{
echo 'Print 2 function : ';
var_dump($arg1);
var_dump($arg2);
echo ‘
’;
}

function applyOne($arg1,$funcName)
{
if(is_array($arg1))
{
$str = var_export($arg1,true);
$code = “return $funcName( $str ,$arg2);”;
}
else $code = “return $funcName(”$arg1", $arg2);";

return create_function(’$arg2’, $code);
}

$printFunction = applyOne(‘string 1’, ‘print1’);
$printFunction(‘arg2 string’);

class obj {
public $var1;
function __construct(){}

function __set_state($array)
{
$obj = new obj;
$obj->var1 = $array[‘var1’];
return $obj;
}
}
$obj = new obj();
$obj->var1 = ‘variable 1’;
$printFunction = applyOne(array($obj), ‘print2’);
$printFunction(‘arg2 string’);
[/PHP]