PHP - Drop down

Hi

I have one date field drop down :

[PHP]$day = $_POST[‘day’];
$mon = $_POST[‘month’];
$year = $_POST[‘year’];
$dob = $year . “-” . $mon . “-” . $day;
$ins = array(
‘d_dob’ => $dob
); [/PHP]

[PHP]

Date Of Birth*: <?php if($day == '') { $day=date(d, strtotime($d_dob)); } $gnrl->getDropdownList(array('1','2','3','4','5','6','7','8','9','10','11','12','13','14','15','16','17','18','19','20','21','22','23','24','25','26','27','28','29','30','31'),$day); ?> <?php if($month == '') { $month=date(m, strtotime($d_dob));
							}
					?>
                          <option value="01" <?php if(in_array('01',explode(',',$month))) echo 'selected="selected"';?> >Jan</option>
                          <option value="02" <?php if(in_array('02',explode(',',$month))) echo 'selected="selected"';?>>Feb</option>
                          <option value="03" <?php if(in_array('03',explode(',',$month))) echo 'selected="selected"';?>>Mar</option>
                          <option value="04" <?php if(in_array('04',explode(',',$month))) echo 'selected="selected"';?>>Apr</option>
                          <option value="05" <?php if(in_array('05',explode(',',$month))) echo 'selected="selected"';?>>May</option>
                          <option value="06" <?php if(in_array('06',explode(',',$month))) echo 'selected="selected"';?>>Jun</option>
                          <option value="07" <?php if(in_array('07',explode(',',$month))) echo 'selected="selected"';?>>Jul</option>
                          <option value="08" <?php if(in_array('08',explode(',',$month))) echo 'selected="selected"';?>>Aug</option>
                          <option value="09" <?php if(in_array('09',explode(',',$month))) echo 'selected="selected"';?>>Sep</option>
                          <option value="10" <?php if(in_array('10',explode(',',$month))) echo 'selected="selected"';?>>Oct</option>
                          <option value="11" <?php if(in_array('11',explode(',',$month))) echo 'selected="selected"';?>>Nov</option>
                          <option value="12" <?php if(in_array('12',explode(',',$month))) echo 'selected="selected"';?>>Dec</option>
                </select>        
                <select name="year" id="year" class="tyextfild validate-selection required">
                        <?php
							if($year == '')
							{
								$year=date(Y, strtotime($d_dob));
							}
                            $gnrl->getDropdownList(array('1960','1961','1962','1963','1964','1965','1966','1967','1968','1969','1970','1971','1972','1973','1974','1975','1976','1977','1978','1979','1980','1981','1982','1983','1984','1985','1986','1987','1988','1989','1990','1991','1992','1993','1994','1995','1996','1997','1998','1999','2000','2001','2002','2003','2004','2005','2006','2007','2008','2009','2010','2011','2012'),$year);
                        ?>

            </select>
                </td>
              </tr>

[/PHP]

This works perfectly. After i select date/month/year,and submit, its showing the results stored in the db without any issues… now i need another date set same thing like this. for ex date/month/year drop down. i tried changing the variable names etc but still it shows incorrect date/month/year (previous data) can help me how can i create another set of this 3 dorp down without issues?

Thanks

You would have to do the saem to the name fields in the form

<select name="year"

to something new

<select name="year_form2"
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