php code problem

if ($showigiteidimage) {
$igitwid_divlnk = “onclick=location.href=’” . get_permalink($igitwid_result->ID) . “’; style=cursor:pointer;”;
$igitwid_output .= ‘<li id=“igit_wid_rpwt_li” style="height:’ . $igitwid_height . 'px; padding-bottom: 10px;" ’ . $igitwid_divlnk . ‘>’;
$igitwid_output .= ’

<img src="<?php $values = get_post_custom_values("tj_video_img_url"); echo $values[0]; ?>" id=“igit_rpwt_thumb” >

’;

here the img src could not read the php code, how to solve this ???

need the custom value function code, what the html output looks like now and what its supposed to look like.

[php]if ($showigiteidimage =?) [/php]
theres no condition

That is the condition. We just cant see what that code is.

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