Need help transferring error messages to another page

General PHP Help
#1

Im trying to create a page that collects personal info from users and registers them. I have a page that contains the registration form which i will call page 1. A second page which I will call page 2, processes the form. A simplified version of page 2 looks like this[php]

<?php if (isset($_POST['submitted'])) { $errors = array(); // Connect to the database. require_once ('config.php'); //Check for errors. //Check to ensure that the password is long enough and is of the right format. if (eregi ("^[[:alnum:]]{8,16}$" , $_POST['password'])) { $b = TRUE; } else { $b = FALSE; $errors[] = 'Please enter a password that consists only of letters and numbers between 8 and 16 characters long.'; } //Check to make sure the password matches the confirmed password. if ($_POST['password'] == $_POST['password2']) { $c = TRUE; $password = $_POST['password']; //Encrypt the password. } else { $c = FALSE; $errors[] = 'The password you entered did not match the confirmed password.'; } //Check to make sure they entered their first name and it's of the right format. if (eregi ("^([[:alpha:]]|-|')+$", $_POST['firstname'])) { $d = TRUE; } else { $d = FALSE; $errors[] = 'Please enter a valid first name.'; } //Check to make sure they entered their last name and it's of the right format. if (eregi ("^([[:alpha:]]|-|')+$", $_POST['lastname'])) { $e = TRUE; } else { $e = FALSE; $errors[] = 'Please enter a valid last name.'; } //Insert data into database. if (empty($errors)) { //query the database. for the sake of simplicity, I wont include the code // Show thank you message echo "

Thank You!

You have been registered"; } else { echo 'You could not be registered, please contact us about the problem and we will fix it as soon as we can.'; } //Display error messages. } else {// if errors array is not empty header("Location: page1.php?message=$errors");//Trying to pass the errors array into the url for page1 } } ?>

[/php]

So the idea is to create an array that contains all the errors. Upon querying the database, if the user completed the fields as required, a thank you message is printed. If not, he is redirected to the page containing the form (page 1) and the array containing the errors is transferred to page 1. Now I will include the relevant section of page 1 whihc is supposed to print the error messages.

[php]

<?php if(isset($_GET['message']) { echo '

Error!

The following error(s) occured:
'; foreach ($errors as $msg) { echo "$msg
\n"; } } ?>

[/php]

I get the following error message when I submit the registration forms with deliberate errors:

Error!

The following error(s) occured:

PHP Error Message

Warning: Invalid argument supplied for foreach() in /home/a4993450/public_html/register_page_content.php on line 66

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Can anyone point out why this error occurs?

#2

Hi there,

An invalid foreach usually means that the variable is either not set or isn’t an array.

#3

Well someone suggested that I convert the errors array to a string, url encode the string b4 passing it to the url on page 2. Then on the form page (page 1), decode the url and and reconvert to an array. I did that and this time, there is no php error but the error messages from the form aren’t printed. Can anyone tell me what I did wrong again? Here are the changes I made to page 2 and 1 respectively:[code]

} else {// if errors array is not empty

    //Conver the errors array into a string
    
    $errors_string = implode(" ", $errors);

    //Encode the imploded string.
    
    $message = urlencode($errors_string);


    header("Location: register_page.php?message=$message");

    
}

[/code]



<div id="error">


                                        <?php   if(isset($_GET['message'])) {

                                                //Decode the url
                                                
                                                $errors_string = urldecode($message);

                                                //Explode the decoded errors string back to an array.
                                        
                                                $errors = explode(" ", $errors_string);

                                                echo '<h3>Error!</h3>
                                                The following error(s) occured:<br />';

       
                                                foreach ($errors as $msg) {
                                                echo "$msg<br/>\n";
                                                }

                                          }

                                        ?>

                                        </div> <!--closes error-->
#4

Unless I’m mistaken, you need to replace (in the second code snippet) urldecode($message) with urldecode($_GET[‘message’])

#5

@smokey. thank u very much. that worked. problem solved :slight_smile:

#6

Ok one more problem which i cant seem to resolve. I don’t know if it’s my html formatting. The error mesages get displayed, one word per line. I actually intended to display each error per line, hence the code
foreach ($errors as $msg) {
echo “$msg
\n”;
}
Any suggestion?

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