I’m having a issue with this.
[php]$GrabDataPoll5 = mysql_query(“SELECT type,pokemon FROM poll_list WHERE removed!=‘yes’”);
$PokeList = array();
while($row = mysql_fetch_array($GrabDataPoll5))
{ $PokeList[] = "'".$row['type']."".$row['pokemon']."'"; }
$PokeList = implode(",", $PokeList);
if(!in_array($Pokemon, $PokeList)) {
$Result = “Select a valid Pokemon.”;
}
[/php]
what errors? Do you get any error messages?
Warning: in_array() [function.in-array]: Wrong datatype for second argument in /home/tpkrpg/public_html/poll.php on line 73
Trying make that results in the while loop into array for the the in_array.
looks to me like you’re passing a string as the second arg instead of an array.
[php]$PokeList = implode(",", $PokeList);
if(!in_array($Pokemon, $PokeList)) {[/php]
comment out the implode line and it should work.
Red 