If Statement with grouped conditions

General PHP Help
#1

I have an array with various keys and values that are properties from a pipe delimited data file. I need to exclude certain users based on if a user (an array within a “data” array) has two specific properties set to two specific values as well as a 3rd value not being set to null. Example:
if ($properties[‘value3’] != null && !($properties[‘value1’] && $properties[‘value2’]))

This statement removes all users that have value3 null and all value1 and all value2, but I want users to only be exclude when a single user has both value1 and value2 set. I still need users that have one or the other values to be included. What am I missing in my logic?

#2

Your needs:
— Remove if value3 null
— Keep if value3 not null AND— either value1 or value2

So…

if ( $properties[‘value3’] != null AND ( $properties[‘value1’] != null OR $properties[‘value2’] != null ) )
if I understand you correctly…

#3

if ( $properties[‘ID’] != null AND !( $properties[‘Department’] == ‘Academic Affairs’ AND $properties[‘Person Type’] == ‘Affiliate’ ) )
I only want to exclude a user that has BOTH Department == ‘Academic Affairs’ AND Person Type’ == ‘Affiliate’ as well as their ‘ID’ not being null. So, you’re answer is close to what I need. I will run it and see.

#4

That only selects users that HAVE the Person Type of ‘Affiliate’ or Department of ‘Academic Affairs’. It needs to allow all other Person Types and Departments. No there yet.

#5

So, your needs:
— ID is not null
— depart = AA
— type = aff

Just remove the parens…
if ( $properties[‘ID’] != null AND $properties[‘Department’] == ‘Academic Affairs’ AND $properties[‘Person Type’] == ‘Affiliate’ )

You can use the && / !! as needed, but, I like to use AND / OR as it is much easier to read.

#6

Sorry for any confusion, but it has to exclude any user that has BOTH depart = AA and type = aff, but allow users with one or the other to pass.

#7

So, your needs:
— ID is not null
— depart = AA
— type = aff

Just remove the parens…
if ( $properties[‘ID’] != null AND $properties[‘Department’] == ‘Academic Affairs’ AND $properties[‘Person Type’] == ‘Affiliate’ )

You can use the && / !! as needed, but, I like to use AND / OR as it is much easier to read.

#8

Is this to define logic flow or something else?

I am a big proponent of using classes and role based allowance.

So, what are you trying to determine based on these results?

#9

Ultimately it is a filter to weed out certain users from an array that will be converted to JSON that will be used by an Angular Controller to render a searchable directory.
As stated in an earlier post of mine, “exclude any user that has BOTH depart = AA and type = aff, but allow users with one or the other (values, ‘Academic Affairs’ or ‘Affiliate’) to pass.”

#10

Does that mean, it’s coming out of a database initially?

#11

I figured out why it wasn’t working as I expected Visual Studio Code’s intellisence suggested a variable that was not correct and I selected it assuming it was the one I had assigned to ‘Department’. I could kick myself for missing this stupid mistake! Sorry to waste your time. Ultimately this was all I needed:

if ($ID != null && !($personType == “Affiliate” && $userDept == ‘Academic Affairs’))

Thanks!

#12

Glad you found a solution. However, if it is coming out of a database, you could make it even easier.

#13

It is coming from a database, but I only have access to an attribute file that it outputs nightly.

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