i did something wrong but what:S can someone help me plz?

[system]

<?php

		$werkdag=intval(date('N'));
		
		if (werkdag==1) {
			$werkdag="Maandag";
		}
		if (werkdag==2) {
			$werkdag="Dinsdag";
		}
		if (werkdag==3) {
			$werkdag="Woensdag";
		}
		if (werkdag==4) {
			$werkdag="Donderdag";
		}
		if (werkdag==5) {
			$werkdag="Vrijdag";
		}
		if (werkdag==6) {
			$werkdag="Zaterdag";
		}
		if (werkdag==7) {
			$werkdag="Zondag";
		}
		
		echo "Het is vandaag ".$werkdag." ";
		
	?>
</body>

[Mines]

Hi, you had just forgotten the variable sign ($) in the parameters so your code should look like this:

[php]

<?php

     $werkdag=intval(date('N'));
     
     if ($werkdag==1) {
        $werkdag="Maandag";
     }
     if ($werkdag==2) {
        $werkdag="Dinsdag";
     }
     if ($werkdag==3) {
        $werkdag="Woensdag";
     }
     if ($werkdag==4) {
        $werkdag="Donderdag";
     }
     if ($werkdag==5) {
        $werkdag="Vrijdag";
     }
     if ($werkdag==6) {
        $werkdag="Zaterdag";
     }
     if ($werkdag==7) {
        $werkdag="Zondag";
     }
     
     echo "Het is vandaag ".$werkdag." ";
     
  ?>

[/php]

May I suggest that you can use switch/case’s instead of if’s, I think the code would look much better then, and just last that you use english variable and function names, it is good practice in coding.

Regards

[AbraCadaver]

Or try an array that may be cleaner and is reusable:

[php]$werkdag = intval(date(‘N’));

$dagen = array(1=>“Maandag”, 2=>“Dinsdag”, 3=>“Woensdag”, 4=>“Donderdag”, 5=>“Vrijdag”, 6=>“Zaterdag”, 7=>“Zondag”);

echo "Het is vandaag " . $dagen[$werkdag];[/php]