First of all, sorry for my bad english.
I have this:
[php]$link = file_get_contents(“http://www.imdbapi.com/?i=tt1285016”);
$json = json_decode($json,true);
echo $json[“Title”];[/php]
and I want to replace tt1285016 with $info[“id”]; (this is something from mysql, first time when i use :((.
If I put echo $info[“id”]; it return exactly what i need: tt1421545.
How can I do that? thank u very much and sorry again for bad enlighs, not native language. 
it’s:
$json = json_decode($link,true);
sorry for mistake.
please do this and reply.. /* Use the below code instead of current code. Here $info["id"] is the value return from database. as you define here */ [php]/* Use the below code instead of current code. Here $info[“id”] is the value return from database. as you define here */
$getcontenturl = “http://www.imdbapi.com/?i=".$info["id”];
$link = file_get_contents($getcontenturl);
$json = json_decode($json,true);
echo $json[“Title”];[/php]
Reply your feedback.
~SR
hi and thank u very much for reply.
I do what u said and i get this error:
Notice: Undefined index: Title in C:\xampp\htdocs\muvi.php on line 9
So i tried echo $json; (without “Title”) and i get Array.
and idea? thanks again.
solved, thank u so much anyway.