I have table(s) whose contents can be

[php]

1004 | QUES | The first 5 terms of a sequence are -18, -12, -6, 0, 6. If this an AP find 10th term: | Q | |

Given: | For a sequence, t_{1} = -18, t_{2} = -12, t_{3} = -6, t_{4 }= 0, t_{5} = 6 | AS1 | ||

To Find: | Whether the sequence is an AP. If so, the 10th term i.e. t10. | AS2 | ||

Solution: | For the given sequence, | AS3 | ||

t_{2} - t_{1} = -12 - (-18) = -12 +18 | From given | AS4 | ||

∴ t_{2} - t_{1} = 6 | ….(1) | AS5 | ||

t_{3} - t_{2} = -6 - (-12) = -6 + 12 | From given | AS6 | ||

∴ t_{3 }- t_{2} = 6 | ….(2) | AS7 | ||

t_{4} - t_{3 }= 0 - (-6) = 0 + 6 | From given | AS8 | ||

∴ t_{4} - t_{3} = 6 | ….(3) | AS9 | ||

t_{5} - t_{4} = 6 - 0 = 6 | ….(4) | AS10 | ||

∴ t_{2} - t_{1} = t_{3 }- t_{2} = t_{4} - t_{3} = t_{5} - t_{4} = 6 | from (1), (2), (3), (4) | AS11 | ||

∴ The difference between the consecutive terms is constant | AS12 | |||

∴ The given sequence is an AP with | AS13 | |||

the first term = a = -18 and common difference = d = 6 | ….(5) | AS14 | ||

Now For an AP, t_{n} = a + (n - 1) d | AS15 | |||

∴ t_{10} = -18 + (10 - 1)(6) | Substituting values | AS16 | ||

∴ t_{10} = -18 + (9)(6) | AS17 | |||

∴ t_{10} = -18 + 54 | AS18 |

I want to remove elements like

height=“21” style=“height:15.75pt”

so that I will get table raw table

having

some information 1 |

some information 2 |

some information 3 |

some information 4 |