function visible javascript

meh · November 12, 2011, 10:06pm

Im new to php and javascript , but im making a change password button where when you press it 2 input boxes appear.
I worked earlier today but now i cant get it to work anymore… i cant find anything wrong in my function (bytt)…which calls on the onclick btnBytt… can anyone help? sorry about the messy code!

<?php include "login.php"; ?> Akademisk tilbakemelding for HiBu

HiBu Emne Evaluering

Vis brukere

<?php if (!empty($_SESSION["Brukernavn"])){ ?>

Min side

Policy

<?php } else { ?>

<fieldset> 
	<form name="loginForm" method="POST" action="login.php">

  		<legend> <h2><b>Innlogging</b></h2></legend>
  		<br>
  		<b>Brukernavn:</b> <input type="text" name="mittbrukernavn" size="20"/>
  		<br>
  		<b>Passord:</b><input type="password" name="mittpassord" size="20" />
  		<br>
        <input type="password" name="nyttpassord" id="nyttpassord" size="20" style="visibility:hidden"/> 
        <br>
        <input type="password" name="bekreftnyttpassord" id="bekreftnyttpassord" size="20" style="visibility:hidden"/>
        <br>
  		<input type="submit" value="Logg inn" name="btnLoggInn"/> 
        <input type="submit" value="Glemt passord" name="btnGlemt" /> 
        <input type="button" value="Bytt passord?" name="btnBytt" onClick="bytt()" />
        <br>

Policy

	</form>
 </fieldset>

<?php } ?>