Hello guys, I hope you can help.
I can’t get my page to switch between two database connections properly 
It seems to ignore the second connection.
I’m trying to go through each group in database one and find out how many members they have registered in database two by checking the field “tsName”.
This is a valid query for database one.
[php]$fetchUsers = mysql_query(“SELECT * FROM $db_corps_table ORDER BY cName;”, $con1);[/php]
This is a valid query for database two.
[php]$fetchUsers = mysql_query(“SELECT * FROM ‘users’ WHERE tsName LIKE $cTicker%;”, $con2);[/php]
However despite me specifying which database link to use it tries to use every query on database one ($con1). So I can never query database two ($con2) because it just breaks with the result below. :S
[php]$fetchUsers = mysql_query(“SELECT * FROM $db_corps_table ORDER BY cName;”, $con1);[/php] gives
AREA 43 [A-43] (11): result result result (there are 3 groups in database one)But: [php]$fetchUsers = mysql_query("SELECT * FROM 'users' WHERE tsName LIKE $cTicker%;", $con2); [/php] gives
AREA 43 [A-43] (11):Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/sever/public_html/mav/tools/ts_corp_registrations.php on line 51
[php]<?php
// ===== Connect to database one (group) =====
$con1 = mysql_connect($db_host,$db_corps_user,$db_corps_pass);
if (!$con1) {
die(“Could not connect:” . mysql_error());
}
$db_select1 = mysql_select_db($db_corps_db, $con1);
if (!$db_select1) {
die (“Could not select database:” . mysql_error());
}
// ===== Connect to database two (members) =====
$con2 = mysql_connect($db_host,$db_ts_user,$db_ts_pass, true);
if (!$con2) {
die(“Could not connect:” . mysql_error());
}
$db_select2 = mysql_select_db($db_ts_db, $con2);
if (!$db_select2) {
die (“Could not select database:” . mysql_error());
}
$fetchCorps = mysql_query(“SELECT * FROM $db_corps_table ORDER BY cName;”, $con1);
while ($row = mysql_fetch_array($fetchCorps)) {
// For each of the results, gather details from database one, then see how many members we can find in database two
$cName = $row[“cName”];
$cTicker = mysql_real_escape_string($row[“cTicker”],$con1);
$cMembers = $row[“cMembers”];
echo $cName." [".$cTicker."] (".$cMembers."):<br />";
// ========================== HERE BE PROBLEMS ==========================
//$fetchUsers = mysql_query("SELECT * FROM $db_corps_table ORDER BY cName;", $con1);
$fetchUsers = mysql_query("SELECT * FROM 'users' WHERE tsName LIKE $cTicker%;", $con2);
// ===================================================================
while ($rowTS = mysql_fetch_array($fetchUsers)) {
echo "result<br />";
}
}
// all done, close DB connections
mysql_close($con2);
mysql_close($con1);
?>[/php]