I’ve inherited a site that holds a form to insert values into a Mysql db. It works fine, but I’ve been asked to add a field and can’t seem to work it out.
The site uses a form where users can check a box, and than add values to that row.
So we have a table:
LangID DepName Output
that holds several language codes (BE; EN, FR, DE,…), department codes and output formats. (e.g. NL - DANL - PDF or UK - DAB - Word)
On the form, a table is displayed for all languages with a checkbox and two dropdown lists. When the checkbox is checked, a row needs to be created for the language with the values in the dropdown lists.
At the moment, I have the languages and checkboxes with two select boxes, which works fine.
The code for this:
[PHP]
<?php
$rowCount=-1;
foreach( $languages as $key=>$value ){
if( isset( $_SESSION['formvalues']['addEntry']['target'] ) ){
if( in_array( $value, $_SESSION['formvalues']['addEntry']['target'] ) )
$selected = " checked=\"checked\"";
else
$selected = "";
}
if( $rowCount == 0 ){
echo "</tr>\n<tr>";
$rowCount = 0;
}else
$rowCount++;
?>
<td align="right">
<?php echo $value; ?><input type="checkbox" name="target[]" value=<?php echo "\"".$value."\"" . $selected; ?> />
<select name="department_<?php echo $value ?>">
<?php
$sqlDepartments = "SELECT depName FROM tbldepartements WHERE langId = '".trim($value)."'";
$departments = mysql_query( $sqlDepartments ) or die( mysql_error() );
while( $department = mysql_fetch_object( $departments ) ): ?>
<?php
$curDepartment = $_SESSION['formvalues']['addEntry']['department'][$value];
if( $curDepartment == utf8_encode($department->depName) )
$optionSelected = ' selected="selected"';
else
$optionSelected = '';
?>
<option value="<?php echo utf8_encode($department->depName); ?>"<?php echo $optionSelected; ?>><?php echo utf8_encode($department->depName); ?></option>
<?php endwhile; ?>
<option value=""></option>
</select>
<select name="Output_<?php echo $value ?>">
<?php
$sqlformats = "SELECT Output FROM tbldepartements WHERE langId = '".trim($value)."'";
$formats = mysql_query( $sqlformats ) or die( mysql_error() );
while( $format = mysql_fetch_object( $formats ) ): ?>
<?php
$curformat = $_SESSION['formvalues']['addEntry']['Output'][$value];
if( $curformat == utf8_encode($format->Output) )
$optionSelected2 = ' selected="selected"';
else
$optionSelected2 = '';
?>
<option value="<?php echo utf8_encode($format->Output); ?>"<?php echo $optionSelected2; ?>><?php echo utf8_encode($format->Output); ?></option><span class="error"> «</span>
<?php endwhile; ?>
<option value=""></option>
</select>
<?php
}
?>
</tr>
</table>
[/PHP]
This creates a row for each language in the DB on the form, with two dropdown lists for each language. When a language is checked, all values are inserted into a new row in the DB.
Language Checkbox Department(dropdown) Output(dropdown)
The values get stored in SESSION (as they are carried to a preview page, and from there to a page that does the insert into mysql)
I’m now trying to add a third field to the row with user input. I’ve tried
[PHP]
]
amount |
<?php
if(isset( $_SESSION[‘formvalues’][‘addEntry’][‘amount’] ) )
$amount= “value=”" . $_SESSION[‘formvalues’][‘addEntry’][‘amount’] . “”";
else
$amount = “”;
?>
/> |
[/PHP
but I'm unable to link the language to the user input field.
If I put the input field outside the off the table, it works. The session value is set and I can insert that value into the DB.
But when I try to set it for each language checked, it doesn’t carry.
How should I normally insert this user input in a foreach loop into a variable that can get processed on another page?
Alos note, I have limited PHP knowledge, and this is a bit much for me 
Kind regards, and if you need more info, let me know and I’ll supply all the needed info.
If I
