$x = 3;
$y = $x++ + 3;
echo $y; // equals 6
echo $y = $x + 3; // equals 7Here the echo y variable yields a 6. Why not 7?
Yet the last equation equals 7.
What am I missing?
$y = $x++ + 3;What you’re doing here, is assigning $y the value of $x + 3, and afterwards increment the value of $x by 1.
$y would have returned 7 after this statement if you would have user the following construction:
$y = ++$x + 3;post-increment $x++
after the operation has finished
pre-increment ++$x
before the operation is carried out
got it, thanks