How to dynamically create four columns per line in a single row with php?

[africa_developeur]

I am trying to create a form where i could display 4columns per line in a single row. the total nber of columns is 8.

I have tried myself but got stucked.I have made display the 1st four tables, but got stuck for the remaining 4 on the next line This is my code.

[php]<?php
$maxCol = 8;
$minCol = 4;

echo ’

Select a size and enter its qty

’;

echo'<div style="padding:5px;">';

for ($j=1; $j < $minCol; $j++) { 
   echo' <select name="">
   <option value="">Select a size</option>
   <option value="1">XL</option>
   <option value="2">XXL</option>';
   echo'</select>';

   echo' <input type="text" size="5" >';

}

echo '</div>';

?>[/php]

How to get display the remaining 4columns on the next line in the same row?

[bashirpatel]

Hi there

The for loop in your code will have only three iterations. Try the following code:

[php]<?php
$maxCol = 11;
$minCol = 4;

echo ’

Select a size and enter its qty

’;

echo’

’;

for ($j=1; $j < $maxCol+1; $j++) {
echo’
Select a size
XL
XXL’;
echo’’;

    echo' <input type="text" size="5" >';
    if ($j % $minCol == 0) echo '<br>'; // Output line break after we've displayed four

}

echo ‘

’;[/php]