I’m expecting the following code testing xor to display ‘false’. But it displays true.
[php]
<?php // wasabi and mustard can't be applied at the same time. $wasabi='a'; $mustard='a'; $outcome= $wasabi xor $mustard; if ($outcome == false) { echo "false"; } if ($outcome == true) { echo "true"; } ?>[/php]
THX
Following works as expected
[php]
<?php // wasabi and mustard can't be applied at the same time. $wasabi='a'; $mustard='a'; if ($wasabi=='a' xor $mustard=='b') { echo 'true'; } ?>[/php]
[php]
<?php // wasabi and mustard can't be applied at the same time. $wasabi=boolval("a")?'true':'false'; $mustard=boolval("a")?'true':'false'; $outcome= $wasabi xor $mustard; echo $wasabi;echo $mustard;echo $outcome; // truetruetrue /* if ($outcome == 'false') { echo "false"; } if ($outcome == 'true') { echo "true"; } */ ?>[/php]
Here $outcome is true even when $wasabi and $mustard are both true. ???
I fixed the error. It was with lower precedence of xor compared with =.
[php]
<?php $outcome=(true xor true); if ($outcome==true) echo "true"; elseif ($outcome==false) echo "false"; ?>[/php]
This works as expected
false
false
true
true
Just to wrap it up the following works as expected
[php]
<?php $outcome=('a' xor 'a'); if ($outcome==true) echo "true"; elseif ($outcome==false) echo "false"; ?>[/php]
I get
false
false
true
true