Database > MySQL database
updating value in table PHP/MySQL
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Nick C.:
Hi, I'm a noob. I have a register/login script which works perfectly. Once the user logs in, I'd like them to be able to change their name. Here is the SQL:
CREATE TABLE `members` (
`member_id` int(11) unsigned NOT NULL auto_increment,
`firstname` varchar(100) default NULL,
`lastname` varchar(100) default NULL,
`login` varchar(100) NOT NULL default '',
`passwd` varchar(32) NOT NULL default '',
PRIMARY KEY (`member_id`)
) TYPE=MyISAM;
I have a form in a file called member_settings.php
<form method="post" action="member_settings_exec.php">
<input name="mem_id" type="hidden" id="mem_id" value="<?php echo $_SESSION['SESS_MEMBER_ID']; ?>">
Name <input name="fname" type="text" id="fname" value="<?php echo $_SESSION['SESS_FIRST_NAME']; ?>">
<input name="update" type="submit" id="update" value="Update">
</form>
And here is member_settings_exec.php (I'll include all the code, because I'm not exactly sure where the problem is):
<?php
//Start session
session_start();
//Include database connection details
require_once('config.php');
//Array to store validation errors
$errmsg_arr = array();
//Validation error flag
$errflag = false;
//Connect to mysql server
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!$link) {
die('We failed to connect to the server: ' . mysql_error());
}
//Select database
$db = mysql_select_db(DB_DATABASE);
if(!$db) {
die("Unable to select database.");
}
//Function to sanitize values received from the form. Prevents SQL injection
function clean($str) {
$str = @trim($str);
if(get_magic_quotes_gpc()) {
$str = stripslashes($str);
}
return mysql_real_escape_string($str);
}
//Sanitize the POST values
$fname = clean($_POST['fname']);
//Input Validations
if($fname == '') {
$errmsg_arr[] = 'You cannot leave this field blank.';
$errflag = true;
}
//If there are input validations, redirect back to the registration form
if($errflag) {
$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
session_write_close();
header("location: member_settings.php");
exit();
}
#mem_id = clean($_POST['mem_id'])
#fname = clean($_POST['fname'])
//Create UPDATE query
$qry = "UPDATE members SET firstname = $fname WHERE member_id = $mem_id" ;
$result = @mysql_query($qry);
//Check whether the query was successful or not
if($result) {
header("location: member-settings.php");
exit();
}else {
die("Operation failed. " .mysql_error());
}
?>
I usually get a syntax error in the $qry line, but I can't figure out what's wrong. I've tried several different approaches and either member_settings_exec.php loads blank or the syntax error. I can't figure out what it is! Any help? (I tried "UPDATE members(firstname) VALUES('$fname') WHERE member_id = $mem_id" to no avail).
cabalsdemon:
please put your code in code line next time so its easier
--- PHP Code: ---
CREATE TABLE `members` (
`member_id` int(11) unsigned NOT NULL auto_increment,
`firstname` varchar(100) default NULL,
`lastname` varchar(100) default NULL,
`login` varchar(100) NOT NULL default '',
`passwd` varchar(32) NOT NULL default '',
PRIMARY KEY (`member_id`)
) TYPE=MyISAM;
I have a form in a file called member_settings.php
<form method="post" action="member_settings_exec.php">
<input name="mem_id" type="hidden" id="mem_id" value="<?php echo $_SESSION['SESS_MEMBER_ID']; ?>">
Name <input name="fname" type="text" id="fname" value="<?php echo $_SESSION['SESS_FIRST_NAME']; ?>">
<input name="update" type="submit" id="update" value="Update">
</form>
And here is member_settings_exec.php (I'll include all the code, because I'm not exactly sure where the problem is):
<?php
//Start session
session_start();
//Include database connection details
require_once('config.php');
//Array to store validation errors
$errmsg_arr = array();
//Validation error flag
$errflag = false;
//Connect to mysql server
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!$link) {
die('We failed to connect to the server: ' . mysql_error());
}
//Select database
$db = mysql_select_db(DB_DATABASE);
if(!$db) {
die("Unable to select database.");
}
//Function to sanitize values received from the form. Prevents SQL injection
function clean($str) {
$str = @trim($str);
if(get_magic_quotes_gpc()) {
$str = stripslashes($str);
}
return mysql_real_escape_string($str);
}
//Sanitize the POST values
$fname = clean($_POST['fname']);
//Input Validations
if($fname == '') {
$errmsg_arr[] = 'You cannot leave this field blank.';
$errflag = true;
}
//If there are input validations, redirect back to the registration form
if($errflag) {
$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
session_write_close();
header("location: member_settings.php");
exit();
}
#mem_id = clean($_POST['mem_id'])
#fname = clean($_POST['fname'])
//Create UPDATE query
$qry = "UPDATE members SET firstname = $fname WHERE member_id = $mem_id" ;
$result = @mysql_query($qry);
//Check whether the query was successful or not
if($result) {
header("location: member-settings.php");
exit();
}else {
die("Operation failed. " .mysql_error());
}
?>
--- End code ---
now it looks like your are not telling the script of update the database that you are doing anything
like this
--- PHP Code: ---
if(isset($_post 'submit' ))
$qry = "UPDATE members SET firstname = $fname WHERE member_id = $mem_id" ;
$result = @mysql_query($qry);
--- End code ---
something like that not tested so work with it
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